Observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3

We have two relations

2*x*y = 6 (2 times x times y is equal to six)

x - y = 3  ( the difference between x and y is trhe)

Where whe have two variables, x and y.

To solve this system, the first step is isolation one of the variables in one of the equations, let's isolate x in the second equation.

x - y = 3

x = 3 + y

now we can replace this in the other equation and then solve it for y.

2*x*y = 6

2*(3 + y)*y = 6

6y + 2y^2 = 6

now we have the quadratic equation:

2y^2 + 6y - 6 = 0

the solutions are:

the solutions are:

y = (-6 + 9,2)/4 = 0.8

y = (-6 - 9.2)/4 = -3.8

if y = 0.8, then:

x = 3 + y = 3.8

if y = -3.8

x = 3 + y = 3 - 3.8 = -0.8

so we have two possible solutions:

(-0.8, -3.8) and (3.8, 0.8)

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)