Evaluate each expression.
6! =
3! - 2!= 1

6!=720

3! • 2!=12

Step-by-step explanation:

We must recall that the factorial of a number n (positive or zero) is the product of all the integers from n down to 1

n!= n(n-1)(n-2)...1

Let's evaluate the given expressions

6!=6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1=720

Similarly

3!\cdot 2!=(3\cdot 2\cdot 1)\cdot (2\cdot 1)=6\cdot 2=12

Finally

\displaystyle \frac{6!}{3!}=\frac{6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{3\cdot 2\cdot 1}

\displaystyle \frac{6!}{3!}= \frac{720}{6}=120

560

hope this : )