The question that follows this graph is:

Which of the following sets of points would be the result of a 180° rotation of SM?

S’(5,1), M’(1,3)

S’(1,5), M’(3,1)

S’(-5,-1), M’(-1,-3)

S’(5,-1), M’(1,-3)

S'(5,-1), M'(1,-3)

Step-by-step explanation:

So, if the rotation is clockwise, the formula is (x,y)--->(-x,-y).

The original points are, (-1,3) and (-5,1).

Using the formula,

(-1,3) > (1,-3)

(-5,1) > (5,-1)

For the question in the image, the reflection over the x-axis is..

S'(-5,1) ---> (-5,-1)

M'(1,-3) ---> (-1,-3)

the answer is c. 23/3

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.