Using the technique in the model above, find the missing segments in this 30°-60°-90° right triangle. BC = 2

We are given triangle ABC.

CD is a perpendicular line on AB.

< B = 60°

BC = 2 units.

We need to find the value of side CD.

In triangle BCD, we can see that <CDB is a right triangle, because CD is a perpendicular line on AB.

And <CBD = 60° that is given.

Therefore, < BCD = 30 degrees angle.

In order to find the value of CD, we can apply 30°-60°-90° right triangle rule to find the value of CD.

According to 30°-60°-90° right triangle rule adjacent side of 60° angle is half of Hypotenuse.

Therefore, BD = Half of BC = 2/2 = 1 unit.

And according to 30°-60°-90° right triangle rule opposite side is \sqrt{3}

3 times of adjacent side of 60° angle.

Therefore, CD = BD × \sqrt{3} 3 = 1×\sqrt{3} 3

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y=mx+

answer: y=0 if that is what u r looking for