A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to
-10.0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three
significant figures

Mass of tin sample

is ≈ 95.7g

Explanation:

This problem bothers on heat calorimetry/capacity of a substance.

Given data

Specific heat capacity of tin

Cp = 0.227 J/g•°C

Initial temperature of tin θ1= 15°C

Final temperature of tin θ2= -10°C

Heat released Q= 543 J

Mass of tin m=

We know that quantity of heat is given as

Q=mcΔθ

Substituting our given data and solving for mass m we have

543= m*0.227*(-10-15)

543= m*0.227*(-25)

543= - 5.675m

m=543/-5.675

= -95.68

Mass of tin is ≈ 95.7g

What is Quantity of heat?

Quantity of heat is the amount of heat absorbed or given out by a body Q=mcθ

56

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!