The table below shows data from a survey about the amount of time students spend doing homework each week. The students were either in college or in high school: High Low Q1 Q3 IQR Median Mean σ College 20 6 8 18 10 14 13.3 5.2 High School 20 3 5.5 16 10.5 11 11 5.4 Which of the choices below best describes how to measure the spread of this data? (2 points) Group of answer choices Both spreads are best described with the IQR. Both spreads are best described with the standard deviation. The college spread is best described by the IQR. The high school spread is best described by the standard deviation. The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

step-by-step explanation:

the equation is not included but the answer is (1.50, 2.00, 2.75)

step-by-step explanation:

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w