Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes. If 10 adult smartphone users are randomly selected, find the probability that at least 5 of them use their smartphones in meetings or classes.

79.85% probability that at least 5 of them use their smartphones in meetings or classes.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they use their smartphone during meetings or classes, or they do not. The probability of an adult using their smartphone in these situations are independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes.

This means that

10 adults selected.

This means that

Find the probability that at least 5 of them use their smartphones in meetings or classes.

In which

79.85% probability that at least 5 of them use their smartphones in meetings or classes.

homozygous. one is homozygous, while two is heterozygous.