What is the equation of the quadratic function with a vertex at (2,-25) and an x-intercept at (7,0)?
f(x) = (x - 2)(x-7)
f(x) = (x + 2)(x + 7)
f(x) = (x – 3)(x + 7)
f(x) = (x + 3)(x – 7)

 f(x) = (x + 3)(x – 7)

Step-by-step explanation:  Use "standard form" of the function and insert values given: vertex (2,-25) intercept point (7,0)

f(x) = a(x-h)² + k   from vertex, h is 2   y is -25   from intercept,  x is 7  f(x) is 0

to find a,  0 = a(7-2)² +(-25)   0 = a(7-2)² -25  add 25 to both sides

25 = a(5)²  25 = 25a  25/25 = a  1=a  (seems useless but verifies implied "a"coefficient is 1)

f(x) = a(x-h)² + k solve to get the quadratic form

f(x) = (x-2)² -25     (x - 2)² is x² -4x +4

f(x) = x² -4x +4 -25  simplify

f(x) = x² -4x - 21   then factor

f(x) = (x + 3)(x - 7)

step-by-step explanation:

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".