What is the slope-intercept form of the function that contains the point (6, 2) and has a slope of 3?

Y - y1 = m(x-x1)
y - 2 = 3(x-6)
y - 2 = 3x - 18
y = 3x -18 +2
y = 3x -16

we are given the point (6,2) and a slope of 3. With these given, we use the point slope form (y-y1) = m* (x-x1) where m is the slope and x1 and y1 are the coordinates of the point given. In this case, upon substitution, the equation is equal to y - 2 = 3 *(x-6). we simplify the equation to y = 3x -16