. (10 points - Bonus problem) The Fredholm alternative states that: If b ∈ R m is not in the column space of Am×n, then it is not orthogonal to the left nullspace of A. Equivalently, using matrix language, we have that either the system Ax = b OR the system AT y = 0 with y T b = 1 has a solution. Verify the Fredholm alternative for the system Ax = b with A =   1 2 3 4 5 6 7 8 9   and b = (0, 1, 1). (Hint: If Ax = b does not have a solution show that AT y = 0 with y T b = 1 has a solution).

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

a

step-by-step explanation:

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx