Two boys decided by a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696 more than they need to pay. What was the price of the computer? Please answer!!!

$433.87

Step-by-step explanation:

Equations:

s = (5/6)f

f = (7/8)c

f + s = c + 696

Substitute for f and for s ; solve for "c":

(7/8)c + (5/6)(7/8)c + c = 696

[1 + (5/6)](7/8)c + c = 696

(11/6)(7/8)c = 696

(77/48)c = 696

computer = 48*696/77 = $433.87

the answer is d

hope this