Please help me on this problem.

Work Shown:

Find the slope of the line through (x1,y1) = (-5,-6) and (x2,y2) = (1,4)

m = (y2 - y1)/(x2 - x1)

m = (4 - (-6))/(1 - (-5))

m = (4 + 6)/(1 + 5)

m = 10/6

m = 5/3

Plug m = 5/3 and (x1,y1) = (-5,-6) into the point slope formula. Solve for y.

y - y1 = m(x - x1)

y - (-6) = (5/3)(x - (-5))

y + 6 = (5/3)(x + 5)

y + 6 = (5/3)x + (5/3)(5)

y + 6 = (5/3)*x + 25/3

y + 6 - 6 = (5/3)*x + 25/3 - 6

y = (5/3)x + 7/3

This equation is in slope intercept form (y = mx+b) with m = 5/3 as the slope and b = 7/3 as the y intercept.

Let's convert this to standard form

y = (5/3)*x + 7/3

3y = 5x + 7   multiply every term by 3 to clear out the fractions

3y-7 = 5x

5x = 3y-7

5x-3y = -7 ... this is in the form Ax+By = C, which is standard form.

17 1/3

step-by-step explanation: