An equilateral triangle has a base of 44 meters and a height of h meters. Inside that triangle is constructed a second equilateral triangle of base 22 meters and a height
of 0.5h meters. Inside the second triangle is constructed a third equilateral triangle of base 11 meters and a height of 0.25h meters.
What percent of the area of the largest triangle is the area of the smallest triangle?
% of the area of the largest triangle.
The area of the smallest triangle is
(Type an integer or a decimal)

6.25 %  of area of Large triangle =  area of smallest triangle

Step-by-step explanation:

Area of large triangle L = (1/2)*base*height

L = (1/2)*(44 m)* h

L = 22*h  square m.

2nd equilateral triangle area:  S =(1/2)*(22 m)*(0.5h)

S = 5.5*h sq. m.

3rd smallest equilateral triangle area : T = (1/2)*(11 m)*(0.25h)

T = 1.375*h sq. m

Find percent P  where  T = P* L,     1.375*h = P * 22*h

P = 6.25%  = 0.0625

there is no question content here, but you for the free points! : d

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d