Can someone solve this factoring trinomial: 4x^2+27-7

Using 5 steps

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4(x^2+5) that's ur answer I did it in 2 steps

Step-by-step explanation:

Subtract 27-7 and u get 4x^2+20.

Now factor and u get 4(x^2+5)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

could you provide figure.