The Saxena family plans to install a light to illuminate part of their rectangular yard. Nikki and Dylan each proposed a
different spot to place the light. The proposed placements and the lit area that each produces are shown below.
Nikki's Proposed Placement
Light
27.5 ft
Dylan's Proposed Placement
Light
16.5
38
38 ft
.
Lit area
Lit Area
60
60ft
How do Nikki's and Dylan's proposals compare? Check all that apply.
Nikki's proposed placement will light a greater area than Dylan's placement.
Dylan's proposed placement will light a greater area than Nikki's placement.
Both proposed placements will light the same sized area.

b. hoped i'm right lol

step-by-step explanation:

final total: 63

step-by-step explanation:

60 times sales tax

60 times 0.05

3

60 + 3

63

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

option b  

step-by-step explanation:

we know that

the distance from point n to lm in the figure is equal to the distance of the perpendicular line to lm that passes through the point n

so

the distance is equal to the segment no

> given problem

therefore

the distance from point n to lm is equal to