A car is bought at the price of $20,000. The value decreases at the rate of .20 every year (t). The exponential expression 20,000(0.80)t describes this situation. Find the price of the car after 3 years.
Question 11 options:

A)

$9,399

B)

$11,874

C)

$10,240

D)

$5,892

y = 20,000 (.80)^t

y = 20,000 (0.80)^3

0.8^3 = 0.512

0.512 x 20,000 = 10240

Your answer would be C. $10,240.

add the table and i will answer correctly

step-by-step explanation:

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.