Rachel has tossed a fair coin ten times. It landed heads up every time. Is this LIKELY?

This is not likely

Explanation:

When Rachel tossed a fair coin ten times, it is not likely she gets heads every time. This is because on a coin there is an head and a tail.

There is an equal chance of obtaining a tail and an head. i.e there is 1/2 chance of obtaining 10 heads and 1/2 chance of obtaining 10 tails.

Hence, the probability of getting heads after tossing the fair coin 10 times

= 1/2¹⁰ = 1/ 1024

This means Rachel would have to carry out a large amount of trials and the calculation above shows that only 1 trial would succeed out of 1024 trials would give Rachel, heads every time she tossed the fair coin 10 times.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

honestly bro aint no one got time to answer these dumb question just do it p***y

step-by-step explanation: