A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a simple random sample 15 cigarettes is 42.6 mg with a standard deviation (s) of 3.7 mg. Is this evidence the nicotine content of the cigarettes exceeds 40 mg? Assume cigarette nicotine content is distributed normally. Use a 1% level of significance (α=0.01) to carry out the appropriate test of significance.

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

represent the average nicotine content

represent the sample standard deviation

sample size  

represent the value to check

represent the significance level for the hypothesis test.  

t would represent the statistic

represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

Null hypothesis:  

Alternative hypothesis:  

The statistic for this case would be:

 (1)  

And replcing we got:

The degrees of freedom are:

The p value would be:

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )