For what value of b does (1/12)^-2b times 12^-2b+2=12?

-1/2
-1/4
1/4
no solution

Always remember

Step-by-step explanation:x^-m=1/x^m

1/12=12^-1

also

(x^m)^n=x^(mn)

also (x^m)(x^n)=x^(m+n)

( \frac{1}{12} )^{-2b}(12)^{-2b+2}=12

( 12^{-1})^{-2b}(12)^{-2b+2}=12

( 12^{2b})(12)^{-2b+2}=12

12^{2b-2b+2}=12

12²=12

so no solution

No solution is right

Step-by-step explanation: