What is the missing constant term in the perfect square that starts with x^2-4xx 2 −4xx, squared, minus, 4, x ?

9514 1404 393

  4

Step-by-step explanation:

The square of a binomial is ...

  (x -a)^2 = x^2 -2ax +a^2

The constant (a^2) is the square of half the x-coefficient: (-2a/2)^2 = a^2.

The missing constant is the square of half of -4, so is (-4/2)^2 = (-2)^2 = 4..

The missing constant is 4.

Additional comment

You can probably see that the constant will always be positive here, so the sign of the x-term can be ignored. We only need to square half the magnitude.

i believe the answer is 323 ft

step-by-step explanation: