5
A sotid metal cylinder 6 inches long and
2 inches in diameter has a hole drilled
through it with a diameter of 1.5 inches.
1.5 in.
12 in.
Which equation could you use to find how
many cubic inches of metat remain after
the hole has been drilled?
A V = (1 +0.75") 6 in.
V = (1 -0.75') in
V (12 - 0.759) 6 in.
V a{1 -0.75)* - 6 in.
B
C

$2,703.06

step-by-step explanation:

add: $2,687.44+ $2,613.09+$2,808.64= $8,109.17

divide by 3 because you added 3 numbers.

$8,109.17/3=

answer: $2,703.06

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

step-by-step explanation: i dont

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!