(PLEASE HELP) Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Write an inequality that would be used to solve for the least amount of money he needs to deposit to avoid a fee.

A. 727.29 + 248.50 − x ≥ 500
B. 727.29 + 248.50 − x ≤ 500
C. 727.29 − 248.50 + x ≥ 500
D. 727.29 − 248.50 − x ≤ 500

Let x represent amount of money that Tony needs to deposit to avoid a fee.

We have been given that Tony has $727.29 in his checking account. He wrote a check for $248.50 today.

Let us find amount of money left in Tony's account after writing a check of $248.50 as:

After depositing x dollars in account, total amount of money in Tony's account would be .

Since Tony must maintain a $500 balance to avoid a fee, so amount of money is his account should be greater than or equal to 500.

We can represent this information in an inequality as:

Therefore, our required inequality would be and option C is the correct choice.

Let us solve for x.

Therefore, Tony must deposit at-least $21.21 to avoid a fee.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.