So right now i'm doing prodigy and I got this question and I can't find out what it is can I have some help the question is The sum of two numbers is 11 and their difference is 3

x = 7

y = 4

Step-by-step explanation:

The sum of two numbers equaling 11 can be written as

x + y = 3

The difference of the two numbers equaling 3 can be written as

x - y = 3

Where x and y represent the unknown numbers

So now we have a system of equations

We can solve for y in the 1st equation by subtracting x on both sides

x + y = 11

y = 11 - x

We can plug the expression for y into the 2nd equation and solve for x

x - (11 - x) = 3

x - 11 + x = 3

2x - 11 = 3

2x = 14

x = 7

Now we can plug 7 for x into any of the equations and solve for y

1st equation:

7 + y = 11

y = 4

2nd equation:

7 - y = 3

-y = -4

y = 4

So, x = 7 and y = 4

Hope this helped!

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37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3