*plis need it* A cattle breeder sold ¾ of his cows. After that, he sold ¾ of the remainder, and there are 16 cows left. How many cows did he have at the beginning?

256 cows

Step-by-step explanation:

Let the total cow be a

3/4 of a

3/4 x a=3a/4

Remainder= a-3a/4=a/4

Remainder=a/4

3/4 Of The remainder

3/4 of a/4

3/4 x a/4=3a/16

New remainder will be

a/4-3a/16=a/16

New remainder is a/16

Therefore: a/16=16

Cross multiplying we get

a=16x16

a=256

step-by-step explanation:

b and c

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you