Suppose you roll a fair six-sided die 25 times. what is the probability that you roll 5 or more 6's on that die?

This can be solved by using the binomial distribution to find the probability of rolling  0,1, 2, 3 or 4 6's in 25 rolls. Then that value of probability is subtracted from 1 to find the probability of 5 or more 6's.


P(2 sixes) = 0.1258
P(3 sixes) = 0.1929

P(0, 1, 2, 3 or 4 sixes) = 0.0105 + 0.0524 + 0.1258 + 0.1929 + 0.2122 = 0.5938
P(5 or more sixes) = 1.0000 - 0.5938 = 0.4062

Bi’m pretty sure hope it works