What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y-4= (x-6) and passes through the point (-2,-2)?
Oy- fx-10
O y=-3x+ 10
O y = {X-1
0 x = 2 x + 1

y = -x-4

Step-by-step explanation:

In this question, we want to find the equation of a line.

Generally, the equation of a starlight line goes by the firm y = mx + c where m represents the slope and c represents the y-intercept

The first equation given, can be rewritten as ;

y = x -6 + 4

y = x - 2

From here, it is clear that our slope m is equal to 1.

Now if two lines are perpendicular, the product of their slopes equals -1

what i’m saying is m1•m2 = -1

Now since we know both lines are perpendicular, then we have the slope of the second line as -1 in value

Now after getting the slope, we need to write the equation using that point that falls on where the line passes through

Using;

y = mx + c for slope -1 and point (-2,-2)

we have;

-2 = -1(-2) + c

-2 = 2 + c

c = -2-2

c = -4

Thus our final equation is where we are having m to be -1 and c = -4

y = -1(x) -4

y = -x-4

ps : different equations in the note and on the screenshot. I followed what’s in the question!

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.