90 percent confidence interval for the proportion difference p1−p2 was calculated to be (0.247,0.325). Which of the following conclusions is supported by the interval?

A. There is evidence to conclude that p1>p2 because 0.325 is greater than 0.247.
B. There is evidence to conclude that p1 C. There is evidence to conclude that p1>p2 because all values in the interval are positive.
D. There is evidence to conclude that p1 E. There is evidence to conclude that p2>p1 because 0.247 and 0.325 are both greater than 0.05.

C

Step-by-step explanation:

Statistics!!

When we have a confidence interval for the difference in proportions or means, our null hypothesis is always that there's no difference. (H0 = p1-p2 = 0.)

If the difference is positive, that means we have sufficient evidence p1>p2.

If it's negative, then we have sufficient evidence p2>p1.

Why not A: incorrect interpretation of the interval

Why not B: doesn't look like a complete answer

Why not D: also doesn't look like a complete answer

Why not E: this confuses the definition of alpha-level and p-value with confidence interval values. If those were p-values and greater or less than an alpha-level, we would reject or fail to reject the null hypothesis. That isn't the case here.

idk man good luck man

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15