Find an angle in the normal range (0° to 360°, or 0 to 2pi radians) whose terminal side points in the same direction as the terminal side of an angle measuring -312°

A

Step-by-step explanation:

Our angle is -312 degrees, but because angles on the unit circle are always periodic and repeat every 2π or 360°, that means if we add a certain multiple of 360 to -312, we should get an angle with the terminal side pointing in the same direction.

Let's add 360 to -312:

-312 + 360 = 48°

Thus, the answer is A.

a. 48°

Step-by-step explanation:

To get an angle between 0 and 360, just keep on adding/subtraction 360° to the given angle till you find an angle in the required interval

-312 + 360 = 48°

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: