If f(x) = 3x – 6, create a table of values for x = –2, –1, 0, 1, 2.

f(-2)=-12,f(-1)=-9,f(0)=-6,f(1)=-3

f(2)=0

Step-by-step explanation:

f(x)=3x-6

f(-2)=3(-2)-6

f(-2)=-6-6

f(-2)=-12

f(-1)=3(-1)-6

f(-1)=-3-6

f(-1)=-9

f(0)=3(0)-6

f(0)=0-6

f(0)=-6

f(1)=3(1)-6

f(1)=3-6

f(1)=-3

f(2)=3(2)-6

f(2)=6-6

f(2)=0

it's both, now can you answer my most recent question?