SOLVE IT! IT MUST BE EGAL WITH ,,1".
I need step by step explain

x = 0

Step-by-step explanation:

-[(3^x - 1)(5^x - 1)] + 1 = 1

Subtract 1 form both sides

-[(3^x - 1)(5^x - 1)] = 0

Divide both sides by -1

(3^x - 1)(5^x - 1) = 0

Equate the factors to 0

3^x - 1 = 0

3^x = 1

Use ln both sides

ln(3^x) = ln(1)

xln(3) = 0

x = 0

5^x - 1 = 0

5^x = 1

Use ln both sides

ln(5^x) = ln(1)

xln(5) = 0

x = 0

The only solution is x = 0

47 - 90 = 43

43 - 180 = x

x = 137

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.