H = -5t2 + 30t + 10
a) What is the Rocket's maximum height?

The maximum height is 55

Step-by-step explanation:

Step 1:  Find the derivative with respect to t

Step 2:  Solve for t

Step 3:  Plug in 3 for t in the original equation

 The maximum height is 55

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.