Draw and classify the polygon with the given vertices. Find the perimeter and the area of the polygon. M(-2,5), N(3,-2), P(-2,-2)

Perimeter = 20.6cm  to 1dp  = 20.60cm to 2dp

Area = Base = 8.6/2 = 4.3 x 4.069  = 17.5cm^2

Height is found 4.07  cos( 54.47deg) 5/8.6 = 4.069cm

Step-by-step explanation:

Right angle side triangle, sides

= MN =8.6cm

= NP=5cm

= PM=7cm

= 25sq + 49sq = 74sq

MN^2 =√74 = 8.60232526704 = 8.6cm

P = 8.6 + 5 + 7 = 20.6cm

Step-by-step explanation:

A graph shows the figure to be a right triangle with a base of 5 units and a height of 7 units. Its hypotenuse will be given by the Pythagorean theorem:

  MN² = MP² +PN²

  MN² = 7² +5² = 74

  MN = √74 ≈ 8.60

__

The perimeter is the sum of the side lengths:

  Perimeter = MN +MP +PN = 8.60 +7 +5

  Perimeter = 20.60 . . . . units

__

The area is given by the area formula:

  Area = 1/2bh = 1/2·5·7 = 35/2

  Area = 17.5 . . . . square units

The polygon is a right triangle with a perimeter of 20.60 units and an area of 17.5 square units

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3