A cone-shaped kitchen funnel has a diameter of 6 inches and a height of 7 inches. About how many times would you need to fill the funnel to fill a cylindrical can that has a radius of 4 inches and a height of 13 inches?
A. 3
B. 4
C. 9
D. 10

  D.  10

Step-by-step explanation:

The volume of the cylinder is given by the formula ...

  V = πr²h

  V = π(4 in)²(13 in) = 208π in³

The volume of a cone 3 inches in radius and 7 inches high is ...

  V = (1/3)πr²h = (1/3)(3 in)²(7 in) = 21π in³

Then the ratio of the volume of the cylinder to that of the cone is ...

  (208π in³)/(21π in³) ≈ 9.905

You would need to fill the funnel about 10 times to fill the can.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.