Lashonda, Carlos, and Jim have a total of 59$ in their wallets. Jim has 2 times what Lashonda has. Carlos has 5$ less than Lashonda. How much does each have?

Lashonda has $16, Jim has $32, and Carlos has $11

Step-by-step explanation:

let's say the amount of money each person has is a variable: L, C, and J for Lashonda, Carlos, and Jim respectively.  

J=2L, and C+5=L, and L+C+J=59.

Let's only use Lashonda for this problem.

(2L)+(L-5)+(L)=59. This is equal to  

4L-5=59. 59+5=64.  

4L=64; 64/4=16, so Lashonda has $16    

If we follow the rules, we get:  

J=32, L=16, and C=11.

x=30

step-by-step explanation:

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents