Identify the graph of the equation. Then find to the nearest degree.
2x2 + 4xy + 4y2 = 0

This represent a single point (0, 0)  in the real plane.

This is a complex graph x = i*y  - y,   there are imaginary numbers.

Step-by-step explanation:

2 xx + 4xy +  4yy = 0

...xx + 2xy + y*y  + yy = 0

(x + y)^2  + yy = 0

if  x is a constant

then the cross sections would be parabolas in the zy-plane

... 2yy + 4xy  - 2xy  + xx = 0

(2yy + 4xy + 2xx -2xx) - 2xy + xx = 0

2(y + x)^2 - 2xx - 2xy + xx = 0

2(y + x)^2 - xx - 2xy  = 0

2(y + x)^2 - xx - 2xy  +yy  - yy = 0

...

(x + y)^2  + yy = 0

x = i*y  - y

if  x = r cos a

y = r sin a

cos a )^2  + cos a sina  + sin a)^2  +  sin a)^2 = 0

cos a sin a + sin a)^2 = -1

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.

saving = more money

step-by-step explanation:

if you have 100 bucks, and you want to buy a candy bar, even if you have one at home, if you choose not to buy it, you save.

~courtney