A rectangle has vertices at (Negative1, 6), (Negative1, Negative2), (3, 6), and (3, Negative 2). Sara says the area of the rectangle is 16 square units and her work is shown below.

Steps
Sara’s Work
Step 1
Base: StartAbsoluteValue negative 1 EndAbsoluteValue + StartAbsoluteValue 3 EndAbsoluteValue = 4
Step 2
Height: StartAbsoluteValue 6 EndAbsoluteValue + StartAbsoluteValue negative 2 EndAbsoluteValue = 4
Step 3
Area: 4 times 4 = 16 square units

Where, if at all, did Sara first make a mistake in finding the area of the rectangle?
Step 1
Step 2
Step 3
no mistake

i’m here for points.

step-by-step explanation:

well if you round, things become much more simple. round 5.95 to 6, 4.25 to 4, and 1.05 to 1. now, add 6+4+1 and that would equal 11. so the items together would equal to about $11.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: