A square garden has an area of 441 m^2.if the path of uniform width surrounding inside the garden is 216m^2,find the width of the path

Area of a square garden = 2, 500 m².

Length of the side of the garden =  √2,500 = 50 m.

Width of the path = 2.5 m.

Path is inside the garden.

Width of the garden that is inside (enclosed) by the path:

         50 - 2 * 2.5 = 45 m.

Length of the garden inside by the path :  = 45 m.

So the area of garden inside the path = 45 * 45 m²

      = 2, 025 m².

Area of the path = 2, 500 - 2, 025 

     = 475 m².

Cost of laying the path = Rs 25 /m² * 475 m²

    = Rs 11, 875.

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answer: the first graph

step-by-step explanation:

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.