What is 125x^9+64y^12 written as a sum of cubes

(5x^3+4y^4)(25x^6-20x^3y^4+16y^8)

Step-by-step explanation:

This one is confusing but you follow the formula a^3+b^3= (a+b)(a^2-ab+b^2).

the answer is n

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18