Assume that a simple random sample has been selected and test the given claim. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Listed below are brain volumes in cm cubed of unrelated subjects used in a study. Use a 0.05 significance level to test the claim that the population of brain volumes has a mean equal to 1100.8 cm cubed. 962 1028 1272 1079 1070 1172 1066 1348 1099

The claim that population has mean brain volumes of 1100.8cm is accepted.

Step-by-step explanation:

H0: mean of sample=mean of population

Mean of sample is= (962+1028+1272+1079+1070+1172+1066+1348+1099)/9=1121.778

Standard Deviation= √((x-mean)²/n)

                                  = 114.8572

for significance level of 0.05, p-value from z-table is 1.645

test statistic: z= (sample mean-population mean) / (sample standard deviation/√sample size)=

z= (1121.778-1100.8) / (114.8572/√9)= 0.548

Since test statistic is less than p-value, we can accept accept the null hypothesis

2.56 is the width of the garden

step-by-step explanation:

a

step-by-step explanation: