Please answer correctly, will mark brainliest

Since the values vary from 0.5 to 4.5, let's take 5 intervals of width 1 unit each

(Lower boundary is included, upper boundary is not)

Average

no. of > frequency

movies

0 - 1 > 1

1 - 2 > 5

2 - 3 > 5

3 - 4 > 2

4 - 5 > 1

For frequencies, just count the data values in each interval

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: