Two alloys of iron have different percentages of iron in them. the first of them weights 6 kg and the second one weights 12 kg. one piece of equal weight was cut off from both alloys. the peice from the first was mixed with the leftover of the second alloy and the peice from the second alloy with the leftover part of the first alloy. as a result the percentage of iron became same in both the alloys. what was the weight of each piece of cut off?

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

explanation:

remove parenthesis:

=

apply rule

=

multiply fractions:

=

=

divide:

=

mordancy.

the awnser is visionary