Consider the figure shown below. Find the value of y.

36x2 + 49y2 = 1,764 the foci are located at: (-√13, 0) and (√13,0) (0, -√13) and (0,√13) (-1, 0) and (1, 0)edit: the answer is (- the square root of 13, 0) and (the square root of 13, 0)

Given: ab ≅ bc and ao ≅ oc ok − angle bisector of ∠boc find: m∠aok

Find the vertex for the parabola given by the function ƒ(x) = −3x2 − 6x.