The relative frequency table shows the results of a survey in which parents were asked how much time their children spend playing outside and how much time they spend using electronics. A 4-column table with 3 rows titled time spent by children. The first column has no label with entries at least 1 hour per day outside, less than 1 hour per day outside, total. The second column is labeled at least 1 hour per day using electronics with entries 2, 42, 44. The third column is labeled less than 1 hour per day using electronics with entries 14, 6, 20. The fourth column is labeled total with entries 16, 48, 64. Given that a child spends at least 1 hour per day outside, what is the probability, rounded to the nearest hundredth if necessary, that the child spends less than 1 hour per day on electronics? 0.22 0.25 0.70 0.88

idk sorry this make my brain hurt

Step-by-step explanation:

ian gonna lie that is way to much

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!