ALGEBRA 2 PROBLEM! SOMEONE PLEASE HELP ME! I’VE BEEN TRYING TO FIGURE THIS OUT FOR THE LONGEST TIME, BUT CAN’T!

E

Step-by-step explanation:

The problem says that triangle BDC lies in the plane k, which means that whatever angle is formed by another point beyond this plane with any of the three segments that form BDC (BD, DC, and BC) is the same as the angle formed by the line connecting the point and the plane.

Here, we're given that AD⊥DC, which means AD forms a 90° angle with DC. Then, since DC is already on the plane, we already know for sure that AD is definitely perpendicular to plane k.

Thus, the answer is E (none of these).

E - none of the above

Step-by-step explanation:

There's no information provided about any lengths/angles being equal so we can't call any of the figures similar or congruent

$9.41

step-by-step explanation:

answer: a

step-by-step explanation: the answer is a due to the rule of symmetry; that a line of symmetry must divide a figure into 2 pieces that are the exact same, only reflected over a line of symmetry. b and c do not have lines of symmetry and would not divide the figure evenly, thus making the answer a.