Help solve please, 25 points give, urgently!
Find a partial solution of a second-order differential equation
y" - 9y = 0 if, y=2 and y'=6 if x=0
y" + 6y' + 9 y = 0 if, y=2 and y'=1 if x=0

the first one

step-by-step explanation:

just id the test.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

i those same problems in math and dont know how to do them

it is impossible.