What is the equation of the following graph in vertex form?

y = (x − 2)2 + 1
y = (x − 1)2 + 2
y = (x + 2)2 + 1
y = (x + 2)2 − 1

y = (x- 2)^2 + 1

Step-by-step explanation:

Because the vertex is at (2, 1)

so  the equation is y = (x- 2)^2 + 1

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.