Two farmhouses A and B are 10.3 km apart. A third farmhouse C is located such
that angle A=83◦ and angle B=59◦. How far is C from A?

Distance between A to C is 16.62km

Step-by-step explanation:

See attached document to get a better illustration of the angle.

A = 83°

B = 53°

C = ?

180° = 83° + 53° + C (sum of angles in a triangle is equal to 180°)

180° = 142° + c

C = 180 - 142

C = 38°

To find the distance AC, we have to use sine rule.

a / sin(A) = b / sin(B) = c / sin(C)

a / sin(A) = c / sin(C)

a /sin83 = 10.31 / sin38

Cross multiply

10.31 * sin83 = a * sin38

10.23 = (0.61566)a

a = 10.23 / 0.61566

a = 16.616 km

a = 16.62km

The distance between A and C is 16.62km

so then what are you asking?

step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.