Write the equation of a line in slope-intercept form that goes through the points
(4, -2) and (-4, -4).

A.
y = 1/4x - 3
B.
y = 4x - 3

C.
y = 4x - 2

d
y = 1/4x - 2

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To find the slope(m), use the slope formula:

   And plug in the two points on the line

(-4, -4) = (x₁, y₁)

(4, -2) = (x₂, y₂)

(two negative signs cancel each other out and become positive)

    Simplify the fraction

     Now that you know the slope, substitute/plug it into the equation

y = mx + b

 To find b, plug in either of the points into the equation, it doesn't matter which, then isolate/get the variable "b" by itself. I will use (4, -2)

-2 = 1 + b    Subtract 1 on both sides to get "b" by itself

-3 = b

 Your answer is A

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2