Given the box plot, will the mean or the median provide a better description of the center?

box plot with min at 6, Q1 at 7.5, median at 8, Q3 at 23, max at 32.5

The mean, because the data distribution is symmetrical
The median, because the data distribution is symmetrical
The mean, because the data distribution is skewed to the right
The median, because the data distribution is skewed to the right

The median, because the data distribution is skewed to the right

Step-by-step explanation:

If the longer part of the box is to the right (or above) the median, the data is said to be skewed right. If the longer part is to the left (or below) the median, the data is skewed left.  The data is skewed right.  The median would be a better estimate, because one or two numbers on the high end will cause the  numbers to be skewed to the right, and the mean to be high

Last one:

The median, because the data distribution is skewed to the right

Step-by-step explanation:

Q1: 7.5

Q2: 8

Q3: 23

Q2 - Q1 = 8 - 7.5 = 0.5

Q3 - Q2 = 23 - 8 = 15

Since Q3 - Q2 > Q2 - Q1,

data is positively (right) skewed

Skeweness occurs because of outliers therefore mean is not a suitable option. Median will provide a better description of the centre

answ5

step-by-step explanation:

u have to pay atttion to me

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240