According to the Directory of Education Statistics, 84% of US students attend public schools, 23% of US students attend college, and 17% of US students attend public colleges. What percentage of US students attend either public school or college? A) 40% B) 61% C) 67% D) 90%

D) 90%

Step-by-step explanation:

We have the percentages of students who go to public schools (84%), those who go to college (23%) and those who go to public college (17%).

We know that if you go to the public college, you go to the college, which means that it is a reduction with respect to the question, which is the percentage that goes to public schools and to the college (either public or private). This means that the percentage of public colleges must be subtracted from college because they are already included.

Therefore, the answer would be:

84% + 23% - 17% = 90%

90% of US students attend either public school or college, so the answer is D)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this